Answer
$x^2-4x \geq 5$
$x^2-4x-5\geq0$
$(x+1)(x-5)\geq0$
$x\leq-1$ and $x\geq5$
Work Step by Step
Step 1: Subtract 5 from both sides of the inequality
Step 2: Factorize Inequality (trinomial)
Step 3: The quadratic inequality is greater and equal to $0$ for $x\leq-1$ and $x\geq5$