Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Chapter 11 Test Prep - Review Exercises - Page 1082: 15

Answer

$${a_8} = - x + 61$$

Work Step by Step

$$\eqalign{ & {a_1} = 6x - 9,\,\,{\text{ }}\,{a_2} = 5x + 1 \cr & {\text{Find }}d \cr & d = {a_2} - {a_1} \cr & d = \left( {5x + 1} \right) - \left( {6x - 9} \right) \cr & d = 5x + 1 - 6x + 9 \cr & d = - x + 10 \cr & {\text{The general term is}} \cr & {a_n} = {a_1} + \left( {n - 1} \right)d \cr & {a_n} = 6x - 9 + \left( {n - 1} \right)\left( { - x + 10} \right) \cr & \cr & {\text{Finding }}{a_8} \cr & {a_8} = 6x - 9 + \left( {8 - 1} \right)\left( { - x + 10} \right) \cr & {a_8} = 6x - 9 + 7\left( { - x + 10} \right) \cr & {a_8} = 6x - 9 - 7x + 70 \cr & {a_8} = - x + 61 \cr} $$
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