Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Chapter 11 Test Prep - Review Exercises - Page 1082: 33

Answer

$${S_\infty } = 36$$

Work Step by Step

$$\eqalign{ & 24 + 8 + \frac{8}{3} + \frac{8}{9} + \cdots \cr & \frac{8}{{24}} = \frac{1}{3},\,\,\,\,\frac{{8/3}}{8} = \frac{1}{3} \cr & {\text{This is a geometric series with }}{a_1} = 24{\text{ and }}r = \frac{1}{3} \cr & {\text{The sum of the series is }}{S_\infty } = \frac{{{a_1}}}{{1 - r}} \cr & {S_\infty } = \frac{{24}}{{1 - 1/3}} \cr & {\text{Simplifying}} \cr & {S_\infty } = 36 \cr} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.