Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Chapter 11 Test Prep - Review Exercises - Page 1082: 34

Answer

$${S_\infty } = - \frac{9}{{20}}$$

Work Step by Step

$$\eqalign{ & - \frac{3}{4} + \frac{1}{2} - \frac{1}{3} + \frac{2}{9} + \cdots \cr & \frac{{1/2}}{{ - 3/4}} = - \frac{2}{3},\,\,\,\,\frac{{ - 1/3}}{{1/2}} = - \frac{2}{3} \cr & {\text{This is a geometric series with }}{a_1} = - \frac{3}{4}{\text{ and }}r = - \frac{2}{3} \cr & {\text{The sum of the series is }}{S_\infty } = \frac{{{a_1}}}{{1 - r}} \cr & {S_\infty } = \frac{{ - 3/4}}{{1 - \left( { - 2/3} \right)}} \cr & {\text{Simplifying}} \cr & {S_\infty } = - \frac{9}{{20}} \cr} $$
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