Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Chapter 11 Test Prep - Review Exercises - Page 1082: 16

Answer

$${S_{12}} = 222$$

Work Step by Step

$$\eqalign{ & {a_1} = 2,\,\,d = 3 \cr & {\text{Calculate }}{S_{12}},{\text{ use }}{S_n} = \frac{n}{2}\left[ {2{a_1} + \left( {n - 1} \right)d} \right]{\text{ with }}n = 12 \cr & {S_{12}} = \frac{{12}}{2}\left[ {2\left( 2 \right) + \left( {12 - 1} \right)\left( 3 \right)} \right] \cr & {\text{Simplifying}} \cr & {S_{12}} = 6\left[ {4 + \left( {11} \right)\left( 3 \right)} \right] \cr & {S_{12}} = 222 \cr} $$
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