Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises - Page 53: 10

Answer

$\color{blue}{\dfrac{7y-8x^2}{x^2y}}$

Work Step by Step

Make the rational expressions similar by using their LCD of $x^2y$ to obtain: $\dfrac{7}{x^2}-\dfrac{8}{y} \\=\dfrac{7\color{magenta}{(y)}}{x^2\color{magenta}{(y)}}-\dfrac{8\color{magenta}{(x^2)}}{y\color{magenta}{(x^2)}} \\=\dfrac{7y}{x^2y}-\dfrac{8x^2}{x^2y} \\=\color{blue}{\dfrac{7y-8x^2}{x^2y}}$
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