Answer
$\color{blue}{\dfrac{8}{y+2}}$
Work Step by Step
Factor the numerator and the denominator then cancel the common factors to obtain:
$\require{cancel}
=\dfrac{-8(-1)(-4+y)}{(y+2)(y-4)}
\\=\dfrac{8(y-4)}{(y+2)(y-4)}
\\=\dfrac{8\cancel{(y-4)}}{(y+2)\cancel{(y-4)}}
\\=\color{blue}{\dfrac{8}{y+2}}$
