Answer
$\color{blue}{\dfrac{8}{9}}$
Work Step by Step
Factor the numerator and the denominator then cancel the common factors to obtain:
$\require{cancel}
=\dfrac{8(k+2)}{9(k+2)}
\\=\dfrac{8\cancel{(k+2)}}{9\cancel{(k+2)}}
\\=\color{blue}{\dfrac{8}{9}}$
