Answer
$\color{blue}{\dfrac{2y+1}{y+1}}$
Work Step by Step
Factor the numerator and the denominator then cancel the common factors to obtain:
$\require{cancel}
=\dfrac{(3y+4)(2y+1)}{(3y+4)(y+1)}
\\=\dfrac{\cancel{(3y+4)}(2y+1)}{\cancel{(3y+4)}(y+1)}
\\=\color{blue}{\dfrac{2y+1}{y+1}}$
