Answer
$\color{blue}{\dfrac{7}{y}}$
Work Step by Step
Factor the binomials, then cancel common factors to obtain:
$\require{cancel}
=\dfrac{y^2(y+1)}{7} \cdot \dfrac{7(7)}{y^3(y+1)}
\\=\dfrac{\cancel{y^2}\cancel{(y+1)}}{\cancel{7}} \cdot \dfrac{7\cancel{(7)}}{\cancel{y^3}y\cancel{(y+1)}}
\\=\color{blue}{\dfrac{7}{y}}$
