Answer
$\color{blue}{\dfrac{m-2}{m+3}}$
Work Step by Step
Factor the numerator and the denominator then cancel the common factors to obtain:
$\require{cancel}
=\dfrac{(m-2)(m-2)}{(m+3)(m-2)}
\\=\dfrac{(m-2)\cancel{(m-2)}}{(m+3)\cancel{(m-2)}}
\\=\color{blue}{\dfrac{m-2}{m+3}}$
