Answer
$\color{blue}{2x^2z^4\sqrt{2x}}$
Work Step by Step
Factor the radicand so that at least one factor is a perfect square to obtain:
$=\sqrt{4(2)(x^4)(x)(z^8)}
\\=\sqrt{(4x^4z^8)(2x)}
\\=\sqrt{2^2(x^2)^2(z^4)^2(2x)}$
Bring out the cube root of the perfect cube factors to obtain:
$=2\cdot x^2\cdot z^4\sqrt{2x}
\\=\color{blue}{2x^2z^4\sqrt{2x}}$
