Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 75: 64

Answer

$\color{blue}{\dfrac{\sqrt{15p}}{3p}}$

Work Step by Step

Rationalize the denominator by multiplying $3p$ to both the numerator and the denominator of the radicand to obtain: $=\sqrt{\dfrac{5(3p)}{(3p)(3p)}} \\=\sqrt{\dfrac{15p}{(3p)^2}}$ Bring out the square root of the denominator to obtain: $=\dfrac{1}{3p} \cdot \sqrt{15p} \\=\color{blue}{\dfrac{\sqrt{15p}}{3p}}$
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