Answer
$\color{blue}{10}$
Work Step by Step
RECALL:
$a^3-b^3=(a-b)(a^2+ab+b^2)$
Use the formula above with $a=\sqrt[3]{11}$ and $b=1$ to obtain:
$(\sqrt[3]{11}-1)(\sqrt{11^2}+\sqrt[3]{11}+1)
\\=(\sqrt[3]{11})^3-1^3
\\=11-1
\\=\color{blue}{10}$
