Answer
$\dfrac{\sqrt[3]{36p^2}}{4p^2}$
Work Step by Step
Rationalize the denominator by multiplying $4p^2$ to both the numerator and denominator of the radicand to obtain:
$=\sqrt[3]{\dfrac{9(4p^2)}{16p^4(4p^2)}}
\\=\sqrt[3]{\dfrac{36p^2}{64p^6}}
\\=\sqrt[3]{\dfrac{36p^2}{(4p^2)^3}}$
Bring out the cube root of the denominator to obtain:
$\\=\color{blue}{\dfrac{\sqrt[3]{36p^2}}{4p^2}}$
