Answer
$\color{blue}{34}$
Work Step by Step
RECALL:
$a^3+b^3=(a+b)(a^2-ab+b^2)$
Use the formula above with $a=\sqrt[3]{7}$ and $b=3$ to obtain:
$(\sqrt[3]{7}+3)(\sqrt{7^2}-3\sqrt[3]{7}+9)
\\=(\sqrt[3]{7})^3+3^3
\\=7+27
\\=\color{blue}{34}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 75: 88
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