Answer
a) $6$$\sqrt[3] 2$
b) $\frac{\sqrt 2}{3}$
c) $\frac{3\sqrt 3}{2}$
Work Step by Step
a) $3$$\sqrt[3] {16}$= $3$$\times$($4^{2}$)$^{1/3}$ = $3$$\times$($2^{4}$)$^{1/3}$ = $6$$\sqrt[3] 2$
b) $\frac{\sqrt {18}}{\sqrt {81}}$= $\frac{\sqrt 9 \times \sqrt 2}{\sqrt 9 \times \sqrt 9}$ = $\frac{\sqrt 2}{3}$
c) $\sqrt {\frac{27}{4}}$ = $\sqrt {\frac{9\times3}{4}}$ = $\frac{\sqrt 9 \times \sqrt3}{\sqrt4}$ = $\frac{3\sqrt 3}{2}$
