Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 27

Answer

a) $2\sqrt 11$ b)$4$ c)$\frac{1}{4}$

Work Step by Step

a)$\frac{\sqrt {132}}{\sqrt 3}=\sqrt {44}=\sqrt 4\times\sqrt {11}=2\sqrt {11}$ b)$\sqrt[3] 2\sqrt[3] {32}=\sqrt[3] {2\times32}=\sqrt[3] {64}=4$ c)$\sqrt[4] {\frac{1}{4}}\sqrt[4] {\frac{1}{64}}=\sqrt[4] {\frac{1}{4}\times\frac{1}{64}}=\sqrt[4] {\frac{1}{256}}=\frac{1}{4}$
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