Answer
a)$2$
b)$-2$
c)$\frac{1}{3}$
Work Step by Step
a)$16^{\frac{1}{4}}=\sqrt[4] {16}=2$
b)$-8^{\frac{1}{3}}=\sqrt[3] {-8}=-2$
c)$9^{-1/2}=\frac{1}{9^{1/2}}=\frac{1}{\sqrt 9}=\frac{1}{3}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 55
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