Answer
a) $|x|$
b)$2x^{2}$
Work Step by Step
a)$\sqrt[4] {x^{4}}=|x|$
b)$\sqrt[4] {16x^{8}}=\sqrt[4] {16}\times\sqrt[4] {x^{8}}=\sqrt[4] {16}\times\sqrt[4] {{(x^{2})}^4}=2x^{2}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 45
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