Answer
a)$3$
b)$-2$
c)$-\frac{1}{2}$
Work Step by Step
a)$27^{1/3}=\sqrt[3] {27}=3$
b)$(-8)^{1/3}=\sqrt[3] {-8}=-2$
c)$-{(\frac{1}{8})}^{1/3}=-\sqrt[3] {\frac{1}{8}}=-\frac{1}{2}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 56
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