Answer
a)$7\sqrt 2$
b)$9\sqrt 3$
Work Step by Step
a)$\sqrt {32}+\sqrt {18}=\sqrt {16}\sqrt {2}+\sqrt 9\sqrt {2}=4\sqrt 2+3\sqrt 2=7\sqrt 2$
b)$\sqrt {75}+\sqrt {48}=\sqrt {25}\sqrt {3}+\sqrt {16}\sqrt {3}=5\sqrt 3+4\sqrt 3=9\sqrt 3$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 49
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