Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 22: 36

Answer

$a)$ $(8m^{-2}n^{4})\Big(\dfrac{1}{2}n^{-2}\Big)=\dfrac{4n^{2}}{m^{2}}$ $b)$ $(3a^{4}b^{-2})^{3}(a^{2}b^{-1})=\dfrac{27a^{14}}{b^{7}}$

Work Step by Step

$a)$ $(8m^{-2}n^{4})\Big(\dfrac{1}{2}n^{-2}\Big)$ $\dfrac{8}{2}m^{-2}n^{4-2}=4m^{-2}n^{2}=\dfrac{4n^{2}}{m^{2}}$ $b)$ $(3a^{4}b^{-2})^{3}(a^{2}b^{-1})$ $(27a^{12}b^{-6})(a^{2}b^{-1})=27a^{12+2}b^{-6-1}=27a^{14}b^{-7}=\dfrac{27a^{14}}{b^{7}}$
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