Answer
$a)$ $(8m^{-2}n^{4})\Big(\dfrac{1}{2}n^{-2}\Big)=\dfrac{4n^{2}}{m^{2}}$
$b)$ $(3a^{4}b^{-2})^{3}(a^{2}b^{-1})=\dfrac{27a^{14}}{b^{7}}$
Work Step by Step
$a)$ $(8m^{-2}n^{4})\Big(\dfrac{1}{2}n^{-2}\Big)$
$\dfrac{8}{2}m^{-2}n^{4-2}=4m^{-2}n^{2}=\dfrac{4n^{2}}{m^{2}}$
$b)$ $(3a^{4}b^{-2})^{3}(a^{2}b^{-1})$
$(27a^{12}b^{-6})(a^{2}b^{-1})=27a^{12+2}b^{-6-1}=27a^{14}b^{-7}=\dfrac{27a^{14}}{b^{7}}$