Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 23: 92

Answer

$6.28698 \times 10^{38}$

Work Step by Step

$\frac{(73.1)(1.6341 \times 10^{28})}{0.0000000019}$ First we need to put everything into scientific notation. So we will end up with this: $\frac{(7.31 \times 10^1)(1.6341 \times 10^{28})}{(1.9 \times 10^{-9})}$ Next we multiply the numerator. In scientific notation we multiply the first number together then add the exponents of 10. Giving us: $\frac{(11.94527 \times 10^{29})}{(1.9 \times 10^{-9})}$ $\frac{(1.194527 \times 10^{30})}{(1.9 \times 10^{-9})}$ Then we divide the numerator and denominator. And similar to multiplying we divide the first numbers then subtract the exponents of 10: (30 - (-9) = 39) $0.628698 \times 10^{39}$ $6.28698 \times 10^{38}$
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