Answer
$\dfrac{3x}{4(3x+5)}; x \ne 0, -\frac{5}{3}$
Work Step by Step
Factor each polynomial completely to obtain:
$=\dfrac{3}{2(x)} \cdot \dfrac{x(x)}{2(3x+5)}$
Cancel the common factors to obtain:
$\require{cancel}
\\=\dfrac{3}{2\cancel{(x)}} \cdot \dfrac{x\cancel{(x)}}{2(3x+5)}
\\=\dfrac{3x}{4(3x+5)}; x \ne 0, -\frac{5}{3}$
($x$ cannot be $0$ and $-\dfrac{5}{3}$ because they make the denominator equal to zero, which in turn makes the rational expression/s undefined.)
