Answer
$\displaystyle \frac{x(5x+1)}{(x-4)(x+3)}$
Work Step by Step
$\displaystyle \frac{3x}{x-4}+\frac{2x}{x+3}=... \quad LCD=(x-4)(x+3)$
$=\displaystyle \frac{3x(x+3)+2x(x-4)}{(x-4)(x+3)}$
$=\displaystyle \frac{3x^{2}+9x+2x^{2}-8x}{(x-4)(x+3)}$
$=\displaystyle \frac{5x^{2}+x}{(x-4)(x+3)}$
$=\displaystyle \frac{x(5x+1)}{(x-4)(x+3)}$
