Answer
$\dfrac{4-x}{x-2}; x \ne 2$
Work Step by Step
The given expression is equivalent to:
$=\dfrac{4}{x-2}+\dfrac{x}{-x+2}
\\=\dfrac{4}{x-2} + \dfrac{x}{-1(x-2)}
\\=\dfrac{4}{x-2} + \dfrac{-x}{x-2}$
The expressions are similar so add the numerators and copy the denominator to obtain:
$=\dfrac{4+(-x)}{x-2}
\\=\dfrac{4-x}{x-2}; x \ne 2$
($x$ cannot be $2$ as it makes the expression undefined.)
