Answer
$\dfrac{x^2-4}{2x-3}; x \ne \frac{3}{2}$
Work Step by Step
The expressions are similar so subtract the numerators and copy the denominator to obtain:
$=\dfrac{x^2-4}{2x-3}; x \ne \frac{3}{2}$
($x$ cannot be $\frac{3}{2}$ as it makes the expression undefined.)
