Answer
$\dfrac{4x-5}{3x+4}; x \ne -\frac{4}{3}$
Work Step by Step
The expressions are similar so subtract the numerators and copy the denominator to obtain:
$=\dfrac{5x-4-(x+1)}{3x+4}
\\=\dfrac{5x-4-x-1}{3x+4}
\\=\dfrac{(5x-x)+(-4-1)}{3x+4}
\\=\dfrac{4x-5}{3x+4}; x \ne -\frac{4}{3}$
($x$ cannot be $-\dfrac{4}{3}$ as it makes the expression undefined.)
