Answer
$\dfrac{3x-2}{x-3}; x \ne 3$
Work Step by Step
The expressions are similar so add the numerators and copy the denominator to obtain:
$=\dfrac{x+1+2x-3}{x-3}
\\=\dfrac{3x-2}{x-3}; x \ne 3$
($x$ cannot be $3$ as it makes the expression undefined.)
