Answer
$\dfrac{3a^7c^{11}}{b}$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}, a \ne0$
(ii) $a^{-m} = \dfrac{1}{a^m}, a \ne0$
Divide the coefficients by each other and the variables by each other to obtain:
$=\dfrac{-24}{-8} \cdot a^{2-(-5)}b^{-2-(-1)}c^{8-(-3)}
\\=3 \cdot a^{2+5}b^{-2+1}c^{8+3}
\\=3a^{7}b^{-1}c^{11}$
Use rule (ii) above to obtain:
$=3a^7 \cdot \dfrac{1}{b} \cdot c^{11}
\\=\dfrac{3a^7c^{11}}{b}$
