Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 80: 79

Answer

$\dfrac{x^{24}}{y^{12}}$

Work Step by Step

RECALL: (i) The quotients-to-powers rule states that: $(\frac{a}{b})^n=\frac{a^n}{b^n}$ (ii) The products-to-powers rule states that: $(xy)^n = x^ny^n$ Use the quotients-to-powers rule to find: $=\dfrac{(x^4)^6}{(y^2)^6}$ Use the product-to-powers rule to find: $\\=\dfrac{x^{4(6)}}{y^{2(6)}} \\=\dfrac{x^{24}}{y^{12}}$
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