Answer
$\dfrac{1}{x^8}$
Work Step by Step
RECALL:
(i) $a^m \cdot a^n = a^{m+n}$
(ii) $a^{-m} = \dfrac{1}{a^m}, a \ne0$
Use rule (i) above to obtain:
$=x^{4+(-12)}
\\=x^{-8}$
Use rule (ii) above to obtain:
$=\dfrac{1}{x^8}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 80: 94
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