Answer
$x^{16}$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}, a\ne0$
(ii) $(a^m)^n = a^{mn}$
Use rule (i) above to obtain:
$=(x^{3-(-5)})^2
\\=(x^{3+5})^2
\\=(x^8)^2$
Use rule (ii) above to obtain:
$=x^{8\cdot 2}
\\=x^{16}$
