Answer
$1$
Work Step by Step
RECALL:
For any non-zero real number $x$, $x^0=1$
Use the rule above to obtain:
$\left(\dfrac{4a^{-5}b^3}{12a^3b^{-5}}\right)^0=1$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 80: 112
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