Answer
$$\frac{8y^{21}}{x^{18}}$$
Work Step by Step
$$(\frac{x^{6}y^{-7}}{2})^{-3}$$
Recall the power rule: $(a^{m})^{n}=a^{mn}$
Thus,
$=\frac{x^{6\cdot-3}y^{-7\cdot-3}}{2^{-3}}$
$=\frac{x^{-18}y^{21}}{2^{-3}}$
Recall the negative exponent rule: $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}} = a^{n}$
Thus,
$=\frac{x^{-18}y^{21}}{2^{-3}}$
$=\frac{2^{3}y^{21}}{x^{18}}$
$=\frac{8y^{21}}{x^{18}}$
