Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.6 - Properties of Integral Exponents - Exercise Set - Page 80: 93

Answer

$\frac{1}{x^9}$

Work Step by Step

$x^3\cdot x^{-12}$ Recall the power rule: $a^{m}\cdot a^{n} = a^{mn}$ Thus, $x^3\cdot x^{-12}$ = $x^{3-12}$ $=x^{-9}$ Recall the negative exponent rule: $=a^{-n} = \frac{1}{a^n}$ Hence, $x^{-9} = \frac{1}{x^9}$
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