Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.4 Trigonometric Functions and Their Inverse - 1.4 Exercises - Page 48: 12

Answer

See graph

Work Step by Step

We are given the function: $f(x)=\cos x$ For the inverse to exist, we must restrict the domain of $f$ so that the function is one-to-one: $D_f=[0,\pi]$ $R_f=[-1,1]$ The domain and range of the inverse $f^{-1}(x)=\cos^{-1}(x)$ are: $D_{f^{-1}}=[-1,1]$ $R_{f^{-1}}=[0,\pi]$ The graph of $f^{-1}$ is symmetrical with the graph of $f$ over the line $y=x$. Graph the functions:
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