Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.4 Trigonometric Functions and Their Inverse - 1.4 Exercises - Page 48: 54

Answer

$$ - \frac{\pi }{2}$$

Work Step by Step

$$\eqalign{ & {\text{Let }}y = {\sin ^{ - 1}}\left( { - 1} \right) \cr & {\text{Use the even/odd property}} \cr & {\text{ }}y = - {\sin ^{ - 1}}\left( 1 \right) \cr & {\text{In the interval }}\left[ { - \frac{\pi }{2},\frac{\pi }{2}} \right]{\text{ }}\sin \theta = 1{\text{ for }}\theta = \frac{\pi }{2},{\text{ then}} \cr & {\sin ^{ - 1}}\left( { - 1} \right) = - \frac{\pi }{2} \cr} $$
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