Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.4 Trigonometric Functions and Their Inverse - 1.4 Exercises - Page 48: 50

Answer

$cos^{-1}(-\frac{\sqrt{2}}{2}) = \frac{3\pi}{4}$

Work Step by Step

The domain of $cos^{-1}(x)$ is $[-1, 1]$ and the range is $[0, \pi]$. $cos(\frac{3\pi}{4}) = -\frac{\sqrt{2}}{2}$, so $cos^{-1}(-\frac{\sqrt{2}}{2}) = \frac{3\pi}{4}$.
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