Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.4 Trigonometric Functions and Their Inverse - 1.4 Exercises - Page 48: 67

Answer

$\tan^{-1}(\sqrt{3}) = \frac{\pi}{3}$

Work Step by Step

Since $\tan(\frac{\pi}{3}) = \sqrt{3}$, that means $\tan^{-1}(\sqrt{3}) = \frac{\pi}{3}$.
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