Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 22

Answer

$\displaystyle \frac{1-ab^{2}}{b^{2}}$

Work Step by Step

$b^{-2}-a$=.........$\displaystyle \frac{1}{a^{n}}=a^{-n}$ ........ $=\displaystyle \frac{1}{b^{2}}-a$=......... common denominator: $b^{2}$ .... $=\displaystyle \frac{1}{b^{2}}-\frac{ab^{2}}{b^{2}}$ $= \displaystyle \frac{1-ab^{2}}{b^{2}}$
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