Answer
$9(6x+2)^{1/2}+3(9x-1)(6x+2)^{-1/2}=\dfrac{3(27x+5)}{(6x+2)^{1/2}}$
Work Step by Step
$9(6x+2)^{1/2}+3(9x-1)(6x+2)^{-1/2}$
Take out common factor $3(6x+2)^{-1/2}$ from the expression:
$9(6x+2)^{1/2}+3(9x-1)(6x+2)^{-1/2}=...$
$...=3(6x+2)^{-1/2}[3(6x+2)+9x-1]=...$
Simplify the expression inside brackets:
$...=3(6x+2)^{-1/2}(18x+6+9x-1)=...$
$...=3(6x+2)^{-1/2}(27x+5)=...$
Change the sign of the exponent of $6x+2$ by putting it as a denominator:
$...=\dfrac{3(27x+5)}{(6x+2)^{1/2}}$
