Answer
$\dfrac{1}{9}$
Work Step by Step
RECALL:
$a^{-m} = \dfrac{1}{a^m}, a \ne0$
Use the rule above to have:
$=-\left(-\dfrac{1}{(-3)^2}\right)
\\=-\left(-\dfrac{1}{9}\right)
\\=\dfrac{1}{9}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 6
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