Answer
$\dfrac{1}{64}$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}$
(ii) $a^{-m} = \dfrac{1}{a^m}, a \ne 0$
Use rule (i) above to have:
$=4^{-2-1}
\\=4^{-3}$
Use rule (ii) above to have:
$=\dfrac{1}{4^3}
\\=\dfrac{1}{64}$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 9
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