Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 47

Answer

$a^{2/3}b^{2}$

Work Step by Step

$\displaystyle \frac{a^{4/3}}{a^{2/3}} \cdot \displaystyle \frac{b^{1/2}}{b^{-3/2}}\qquad$ ....... use $\displaystyle \frac{a^{m}}{a^{n}}=a^{m-n}$ $=a^{4/3-2/3}\cdot b^{1/2-(-3/2)}\qquad$ .......simplify exponents $=a^{2/3}b^{4/2}$ $=a^{2/3}b^{2}$
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