Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 38

Answer

3

Work Step by Step

$27^{2/3}\cdot 27^{-1/3}=$ ...use: $a^{m}\cdot a^{n}=a^{m+n}$ $=27^{(2/3)+(-1/3)}$ $=27^{2/3-1/3}$ $=27^{1/3}=$ ... recognize: $27=3^{3}$ $=(3^{3})^{1/3}=$ ...use: $(a^{m})^{n}=a^{mn}$ $=3^{1}=3$
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