Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter R - Algebra Reference - R.6 Exponents - R.6 Exercises - Page R-25: 53

Answer

$5x(x^2-1)^{-1/2}(2x^2-\frac{1}{x^2-1})$

Work Step by Step

$10x^3(x^2-1)^{-1/2}-5x(x^2-1)^{1/2}$ greatest common factor is $5x(x^2-1)^{-1/2}$ $=[5x(x^2-1)^{-1/2}].2x^2-[5x(x^2-1)^{-1/2}].(x^2-1)^{-1}$ $=5x(x^2-1)^{-1/2}(2x^2-\frac{1}{x^2-1})$
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