Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.5 - Factoring Polynomials - Exercise Set - Page 69: 111

Answer

$(x-y)^{2}(x-y+2)(x-y-2)$

Work Step by Step

$(x-y)^{4}-4(x-y)^{2}=$... factor out $(x-y)^{2}$ $=(x-y)^{2}[(x-y)^{2}-4]$ ... the brackets hold a difference of squares $=(x-y)^{2}[(x-y)+2]\cdot[(x-y)-2]$ = $(x-y)^{2}(x-y+2)(x-y-2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.