Answer
$(x+2)(x-3)(x+3)$
Work Step by Step
Regroup to obtain:
$=(x^3+2x^2) + (-9x-18)$
Factor out $x^2$ in the first group and $-9$ in the second to obtain:
$=x^2(x+2) + (-9)(x+2)
\\=x^2(x+2) - 9(x+2)$
Factor out the GCF of $x+2$ to obtain:
$=(x+2)(x^2-9)
\\=(x+2)(x^2-3^2)$
Factor the difference of two squares using the formula $a^2-b^2=(a-b)(a+b)$ to obtain:
$=(x+2)(x-3)(x+3)$
